(1/x^2)-(7/x)+12=0

Solution for (1/x^2)-(7/x)+12=0 equation:

D( x )

x = 0

x^2 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

1/(x^2)-(7/x)+12 = 0

1/(x^2)-7*x^-1+12 = 0

x^-2-7*x^-1+12 = 0

t_1 = x^-1

1*t_1^2-7*t_1^1+12 = 0

t_1^2-7*t_1+12 = 0

DELTA = (-7)^2-(1*4*12)

DELTA = 1

DELTA > 0

t_1 = (1^(1/2)+7)/(1*2) or t_1 = (7-1^(1/2))/(1*2)

t_1 = 4 or t_1 = 3

t_1 = 3

x^-1-3 = 0

1*x^-1 = 3 // : 1

x^-1 = 3

-1 < 0

1/(x^1) = 3 // * x^1

1 = 3*x^1 // : 3

1/3 = x^1

x = 1/3

t_1 = 4

x^-1-4 = 0

1*x^-1 = 4 // : 1

x^-1 = 4

-1 < 0

1/(x^1) = 4 // * x^1

1 = 4*x^1 // : 4

1/4 = x^1

x = 1/4

x in { 1/3, 1/4 }